Write the formula of resonant frequency.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) In an $LCR$ series circuit,resonance occurs when the inductive reactance $(X_L)$ equals the capacitive reactance $(X_C)$.
Given $X_L = X_C$,we have $\omega L = \frac{1}{\omega C}$.
Rearranging for angular frequency $\omega$,we get $\omega^2 = \frac{1}{LC}$,which implies $\omega = \frac{1}{\sqrt{LC}}$.
Since $\omega = 2\pi f$,the resonant frequency $f_r$ is given by $f_r = \frac{1}{2\pi \sqrt{LC}}$.

Explore More

Similar Questions

An $AC$ voltage $V = 220 \sin(2 \times 10^3 t) \text{ V}$ is applied to a series $LCR$ circuit. The current amplitude in this circuit is: (Given: $L = 10 \text{ mH}$, $C = 25 \mu\text{F}$, $R = 100 \Omega$) (in $\text{ A}$)

Obtain the equation of bandwidth for an $L-C-R$ series $AC$ circuit and deduce the equation of $Q$ factor.

The $Q$ factor of a series $LCR$ circuit with $L = 2 \ H$,$C = 32 \ \mu F$,and $R = 10 \ \Omega$ is:

Difficult
View Solution

In a series resonant $LCR$ circuit,for the power dissipated to become half of the maximum power dissipated,the current amplitude is

$A$ circuit of negligible resistance has an inductor of $0.16 H$ and a capacitor of $25 \mu F$ connected in series with an alternating voltage source. The resonant frequency of the circuit is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo